Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Appendix C - C - Exercise Set - Page 686: 22

Answer

$7\frac{7}{8}=7.875$ cubic feet

Work Step by Step

The volume $(V)$ of a rectangular box is given by the formula: $V=lwh$ where $l$=length $w$=width $h$=height The given rectangular ice chest has: $l=3$ ft $w=1\frac{1}{2}$ ft $h=1\frac{3}{4}$ Using the formula above gives: $V=(3\text{ ft})(1\frac{1}{2}\text{ ft})(1\frac{3}{4}\text{ ft}) \\V=7\frac{7}{8}\text{ ft}^3=7.875 \text{ ft}^3$ Therefore, the capacity of the rectangular ice chest is $7\frac{7}{8}=7.875$ cubic feet.
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