Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Appendix C - C - Exercise Set: 7

Answer

$\frac{13}{6}$

Work Step by Step

A 2x2 determinant can be calculated as $ad-bc$, where a is the upper-left entry, b is the upper-right entry, c is the lower-left entry, and d is the lower-right entry. Therefore, the value of the determinant is $(\frac{3}{4}\times\frac{7}{3})-(\frac{5}{2}\times-\frac{1}{6})=\frac{7}{4}-(-\frac{5}{12})=\frac{7}{4}+\frac{5}{12}=\frac{21}{12}+\frac{5}{12}=\frac{26}{12}=\frac{13}{6}$
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