Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.6 - Exponential and Logarithmic Equations; Further Applications - 9.6 Exercises - Page 630: 26

Answer

$x=\dfrac{\pi}{2}$

Work Step by Step

Using the properties of logarithms, the given equation, $ \ln e^{2x}=\pi $ is equivalent to \begin{align*}\require{cancel} 2x\ln e&=\pi &(\text{use }\log_b x^y=y\log_b x) \\ 2x(1)&=\pi &(\text{use }\ln e=1) \\ 2x&=\pi \\\\ \dfrac{\cancel2x}{\cancel2}&=\dfrac{\pi}{2} \\\\ x&=\dfrac{\pi}{2} .\end{align*} Hence, the solution to the equation $ \ln e^{2x}=\pi $ is $ x=\dfrac{\pi}{2} $.
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