Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter 9 - Section 9.6 - Exponential and Logarithmic Equations; Further Applications - 9.6 Exercises - Page 630: 24

Answer

$x\approx43.301$

Work Step by Step

Using the properties of logarithms, the given equation, $ \ln e^{0.04x}=\sqrt{3} $ is equivalent to \begin{align*}\require{cancel} 0.04x\ln e&=\sqrt{3} &(\text{use }\log_b x^y=y\log_b x) \\ 0.04x(1)&=\sqrt{3} &(\text{use }\ln e=1) \\ 0.04x&=\sqrt{3} .\end{align*} Using the properties of equality, the equation above is equivalent to \begin{align*}\require{cancel} \dfrac{\cancel{0.04}x}{\cancel{0.04}}&=\dfrac{\sqrt{3}}{0.04} \\\\ x&=\dfrac{\sqrt{3}}{0.04} \\\\ x&\approx43.301 .\end{align*} Hence, the solution to the equation $ \ln e^{0.04x}=\sqrt{3} $ is $ x\approx43.301 $.
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