Answer
$$\frac{2x^2+6x+1}{\left(x+2\right)\left(x-3\right)\left(x+3\right)}$$
Work Step by Step
We know the following:
$$ (f+g)(x)=f(x)+g(x)$$
Thus, we find:
$$\frac{x-1}{x^2-x-6}+\frac{x+2}{x^2-9}\\ \frac{2x^2+6x+1}{\left(x+2\right)\left(x-3\right)\left(x+3\right)}$$