Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 7 - Functions and Graphs - 7.4 The Algebra of Functions - 7.4 Exercise Set: 29

Answer

$\dfrac{7}{2}$

Work Step by Step

RECALL: $(G/F)(x) = \dfrac{G(x)}{F(x)}$ Using the formula above gives: $(F/G(x) \\= \dfrac{G(x)}{F(x)} \\=\dfrac{5-x}{x^2-2}$ To evaluate the given expression, substitute $-2$ to $x$ in the equation above to obtain: $(G/F)(x) \\=\dfrac{5-x}{x^2-2} \\=\dfrac{5-(-2)}{(-2)^2-2} \\=\dfrac{5+2}{4-2} \\=\dfrac{7}{2}$
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