Answer
$0$
Work Step by Step
RECALL:
$(f-g)(x) = f(x) - g(x)$
Using the formula above gives:
$(f-g)(x) = (-2x+3)-(x^2-5)
\\(f-g)(x)= -2x+3-x^2-(-5)
\\(f-g)(x)= -2x+3-x^2+5
\\(f-g)(x)= -x^2-2x+(3+5)
\\(f-g)(x)= -x^2-2x+8$
Thus, to evaluate the given expression, substitute 2 to the equation above to obtain:
$f(2) -g(2)
\\= (f-g)(2)
\\= -2^2-2(2)+8
\\=-4-4+8
\\=-8+8
\\=0$