Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Study Summary - Practice Exercises - Page 295: 7

Answer

$\dfrac{x^{10}}{7^5}$

Work Step by Step

RECALL: (1) $\left(\frac{a}{b}\right)^m=\frac{a^m}{b^m}$ (2) $(a^m)^n=a^{mn}$ Use rule (1) above to obtain: $\left(\dfrac{x^2}{7}\right)^5=\dfrac{(x^2)^5}{7^5}$ Use rule (2) above to obtain: $=\dfrac{x^{2(5)}}{7^5} \\=\dfrac{x^{10}}{7^5}$
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