Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Study Summary - Practice Exercises - Page 295: 5

Answer

$y^{15}$

Work Step by Step

RECALL: $(a^m)^n=a^{mn}$ Thus, $(y^5)^3=y^{5(3)}=y^{15}$
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