Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Study Summary - Practice Exercises: 9

Answer

$\dfrac{y^3}{x}$

Work Step by Step

RECALL: $a^{-m} = \dfrac{1}{a^m}, m\gt0$ Use the rule above to obtain: $\dfrac{x^{-1}}{y^{-3}}=\dfrac{\frac{1}{x^1}}{\frac{1}{y^3}}$ Use the rule $\frac{a}{b} \div \frac{c}{d}=\frac{a}{b} \times \frac{d}{c}$ to obtain: $=\dfrac{1}{x} \cdot \dfrac{y^3}{1} \\=\dfrac{y^3}{x}$
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