Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 54

Answer

$-6t^3-3t^2+2t+1$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $ (1+2t)(1-3t^2) $, is equivalent to \begin{array}{l}\require{cancel} 1(1)+1(-3t^2)+2t(1)+2t(-3t^2) \\\\= 1-3t^2+2t-6t^3 \\\\= -6t^3-3t^2+2t+1 .\end{array}
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