Answer
$-3n^2-19n+14$
Work Step by Step
Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of $2$ binomials, the given expression, $
(-3n+2)(n+7)
$, is equivalent to
\begin{array}{l}\require{cancel}
-3n(n)-3n(7)+2(n)+2(7)
\\\\=
-3n^2-21n+2n+14
\\\\=
-3n^2-19n+14
.\end{array}