Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.6 Special Products - 4.6 Exercise Set: 63

Answer

$a^3-a^2-10a+12$

Work Step by Step

Using $a(b+c)=ab+ac$ or the Distributive Property, the given expression, $ (a-3)(a^2+2a-4) $, is equivalent to \begin{array}{l}\require{cancel} a(a^2)+a(2a)+a(-4)-3(a^2)-3(2a)-3(-4) \\\\= a^3+2a^2-4a-3a^2-6a+12 \\\\= a^3+(2a^2-3a^2)+(-4a-6a)+12 \\\\= a^3-a^2-10a+12 .\end{array}
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