Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.2 Rational Numbers as Exponents - 10.2 Exercise Set: 34

Answer

$27y^{9}$

Work Step by Step

Using $a^{m/n}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m$, the given expression, $ (9y^6)^{3/2} ,$ is equivalent to \begin{array}{l}\require{cancel} \sqrt[]{(9y^6)^{3}} \\\\= \left( \sqrt[]{9y^6} \right)^3 \\\\= \left( \sqrt[]{(3y^3)^2} \right)^3 \\\\= \left( 3y^3 \right)^3 \\\\= 3^3y^{3(3)} \\\\= 27y^{9} .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.