Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.2 Rational Numbers as Exponents - 10.2 Exercise Set - Page 641: 108

Answer

$$x=-2,\:x=3$$

Work Step by Step

Solving the equation by factoring, we obtain: $$ x^2-x-6=0\\ \left(x+2\right)\left(x-3\right)=0\\ x=-2,\:x=3$$
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