Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - 10.2 Rational Numbers as Exponents - 10.2 Exercise Set - Page 641: 64

Answer

$\dfrac{x^4}{\sqrt[3]{2}\sqrt[7]{y^2}}$

Work Step by Step

Using the laws of exponents, the given expression, $ 2^{-1/3}x^4y^{-2/7} ,$ is equivalent to \begin{array}{l}\require{cancel} \dfrac{x^4}{2^{1/3}y^{2/7}} .\end{array} Using $a^{m/n}=\sqrt[n]{a^m}=(\sqrt[n]{a})^m$, the expression, $ \dfrac{x^4}{2^{1/3}y^{2/7}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{x^4}{\sqrt[3]{2^1}\sqrt[7]{y^2}} \\\\= \dfrac{x^4}{\sqrt[3]{2}\sqrt[7]{y^2}} .\end{array}
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