Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.3 Fraction Notation - 1.3 Exercise Set: 33

Answer

$2\times3\times5\times7$

Work Step by Step

A number is prime if it has only two factors: 1 and itself. We know that the factors of 210 are 1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 70, 105, and 210. 2 is a prime number, so we can divide 210 by 2 $210\div2=105$ The factors of 105 are 1, 3, 5, 7, 15, 21, 35, and 105. Since 3 is a prime number, divide by 3. $105\div3=35$ The factors of 35 are 1, 5, 7 and 35. Since 5 is a prime number, divide by 5. $35\div5=7$ 7 is also a prime number Therefore, the prime factorization of 210 is $2\times3\times5\times7$.
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