Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 1 - Introduction to Algebraic Expressions - 1.3 Fraction Notation - 1.3 Exercise Set: 28

Answer

$2\times3^{3}$

Work Step by Step

A number is prime if it has only two factors: 1 and itself. We know that the factors of 54 are 1, 2, 3, 6, 9, 18, 27, and 54. 2 is a prime number, so we can divide 54 by 2 $54\div2=27$ The factors of 27 are 1, 3, 9, and 27. Since 3 is a prime number, divide by 3. $27\div3=9$ The factors of 9 are 1, 3, and 9. Since 3 is a prime number, divide by 3. 3 is also a prime number Therefore, the prime factorization of 54 is $2\times3\times3\times3=2\times3^{3}$.
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