Answer
$2^{3}\times7$
Work Step by Step
A number is prime if it has only two factors: 1 and itself.
We know that the factors of 56 are 1, 2, 4, 7, 8, 14, 28, and 56.
2 is a prime number, so we can divide 56 by 2
$56\div2=28$
The factors of 28 are 1, 2, 4, 7, 14, and 28. Since 2 is a prime number, divide by 2.
$28\div2=14$
The factors of 14 are 1, 2, 7, and 14. Since 2 is a prime number, divide by 2.
$14\div2=7$
7 is also a prime number
Therefore, the prime factorization of 56 is $2\times2\times2\times7=2^{3}\times7$.
