College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises: 19

Answer

(a) 4 (b) 2 (c) 1/2

Work Step by Step

(a) $\sqrt{16}=\sqrt{4^2}=4$ (b) $\sqrt[4]{16}=\sqrt[4]{2^{4}}=2$ (c) $\displaystyle \sqrt[4]{\frac{1}{16}}=\sqrt[4]{(\frac{1}{2})^{4}}=\frac{1}{2}$
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