College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Section P.4 - Rational Exponents and Radicals - P.4 Exercises - Page 29: 31

Answer

$2x^2$

Work Step by Step

$\sqrt[4]{16x^{8}}=\sqrt[4]{2^{4}x^{2*4}}=2x^{2}$
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