## College Algebra 7th Edition

$2y\sqrt[5]{y}$
The given radical can be written as: $=\sqrt[5]{2^5y^6} \\=\sqrt[5]{(2^5y^5)y}$ RECALL: (i) $\sqrt[n]{a^n} = |a|$ when $n$ is even (ii) $\sqrt[n]{a^n} = a$ when $n$ is odd The given radical has n=5, which is odd. Use rule (ii) above to obtain: $=2\cdot y\sqrt[5]{y} \\=2y\sqrt[5]{y}$