College Algebra 7th Edition

Published by Brooks Cole

Chapter P, Prerequisites - Chapter P Review - Exercises: 9

Answer

(a) $\frac{3}{2}$ (b) $\frac{1}{6}$

Work Step by Step

We find common denominators and reduce: (a) $\displaystyle \frac{5}{6}+\frac{2}{3}=\frac{5}{6}+\frac{4}{6}=\frac{9}{6}=\frac{3}{2}$ (b) $\displaystyle \frac{5}{6}-\frac{2}{3}=\frac{5}{6}-\frac{4}{6}=\frac{1}{6}$

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