College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter P, Prerequisites - Chapter P Review - Exercises - Page 76: 30

Answer

16

Work Step by Step

We use exponent rules to simplify: $64^{2/3}=(4^{3})^{2/3}=4^{2}=16$
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