Answer
(a) $y^{3/2}$
(b) $y^{1/4}$
Work Step by Step
(a) $\sqrt{y^{3}}=(y^{3})^{1/2}=y^{3/2}$
(b) $(\sqrt[8]{y})^{2}=(y^{1/8})^{2}=y^{1/4}$
College Algebra 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305115546
ISBN 13:
978-1-30511-554-5
Chapter P, Prerequisites - Chapter P Review - Exercises - Page 76: 38
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