College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Exercises - Page 426: 97

Answer

(a). $n(t)=30e^{0.15t}$ (b). $n(4)=54.66$ (c).$t=18.75$ year

Work Step by Step

The formula for exponential population growth is, $n(t)=n_0e^{rt}$. Whereas, $n_0$ is the Initial population, $r$ is the growth rate, and $n(t)$ is the population at time $t$. $n(t)=n_0e^{rt}$, $n_0=30$, $r=0.15$ (a). $n(t)=30e^{0.15t}$ (b). $n(4)=30e^{0.15\times4}=54.66$ (c). $500=30e^{0.15t}$, $16.66=e^{0.15t}$, $\ln 16.66=0.15t$, $t=18.75$ year
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