College Algebra 7th Edition

We are given: $[\mathrm{H}^{+}]=1.3\times 10^{-8}$ M $\mathrm{p}\mathrm{H}_{egg\ whites}=-\log[\mathrm{H}^{+}]=-\log(1.3\times 10^{-8})\approx 7.9$ Since we have pH$\gt7$, the egg whites are basic.