College Algebra 7th Edition

Published by Brooks Cole
ISBN 10: 1305115546
ISBN 13: 978-1-30511-554-5

Chapter 4, Exponential and Logarithmic Functions - Chapter 4 Review - Exercises - Page 426: 98

Answer

(a). $h=0.7565$ (b). $n(3)=156233.42$

Work Step by Step

The formula for exponential population growth is, $n(t)=n_0e^{rt}$. Whereas, $n_0$ is the Initial population, $r$ is the growth rate, and $n(t)$ is the population at time $t$. $n_0=10000$, $t=1, n(1)=25000$, (a). $n(t)=n_02^{t/h}$, Whereas $h$ is the doubling time. Therefore, $n(1)=10000\times2^{1/h}=25000$, $2^{1/h}=2.5$, $\frac{1}{h}\log 2=\log2.5$, $h=0.7565$ (b). $n(3)=10000\times2^{3/0.7565}=156233.42$
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