College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.5 - Page 652: 18

Answer

Solution set = $\displaystyle \{(4,\frac{1}{3})\}$

Work Step by Step

$D= $determinant of the coefficient matrix $=\left|\begin{array}{ll} 2 & -9\\ 3 & -3 \end{array}\right|=2(-3)-(-9)(3)=21$ $D_{x}=$ in D, replace the x column with the constants column $=\left|\begin{array}{ll} 5 & -9\\ 11 & -3 \end{array}\right|=-15+99=84$ $D_{y}=$ in D, replace the x column with the constants column $=\left|\begin{array}{ll} 2 & 5\\ 3 & 11 \end{array}\right|=22-15=7$ $x=\displaystyle \frac{D_{x}}{D}=\frac{84}{21}=4$ $y=\displaystyle \frac{D_{y}}{D}=\frac{7}{21}=\frac{1}{3}$ Solution set = $\displaystyle \{(4,\frac{1}{3})\}$
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