College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.5 - Page 652: 19

Answer

Solution set = $\{(4,2)\}$

Work Step by Step

$D= $determinant of the coefficient matrix $=\left|\begin{array}{ll} 3 & -4\\ 2 & 2 \end{array}\right|=3(2)-(-4)(2)=14$ $D_{x}=$ in D, replace the x column with the constants column $=\left|\begin{array}{ll} 4 & -4\\ 12 & 2 \end{array}\right|=8+48=56$ $D_{y}=$ in D, replace the x column with the constants column $=\left|\begin{array}{ll} 3 & 4\\ 2 & 12 \end{array}\right|=36-8=24$ $x=\displaystyle \frac{D_{x}}{D}=\frac{56}{14}=4$ $y=\displaystyle \frac{D_{y}}{D}=\frac{28}{14}=2$ Solution set = $\{(4,2)\}$
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