College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 6 - Matrices and Determinants - Exercise Set 6.5 - Page 652: 9

Answer

$-\frac{7}{16}$

Work Step by Step

For a matrix with the following components, [$a_{1}$ $b_{1}$ $a_{2}$ $b_{2}$], we know that the determinant is calculated as $a_{1}b_{2}-a_{2}b_{1}$. Therefore, the determinant for the given matrix is equal to $(\frac{1}{2})(-\frac{3}{4})-(\frac{1}{8})(\frac{1}{2})=-\frac{3}{8}-\frac{1}{16}=-\frac{3\times2}{8\times2}-\frac{1}{16}=-\frac{6}{16}-\frac{1}{16}=\frac{-6-1}{16}=-\frac{7}{16}$.
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