College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2: 68

Answer

$x=3$ conditional equation

Work Step by Step

$\frac{3}{x-3}=\frac{x}{x-3}+3$ $\frac{3}{x-3}=\frac{x}{x-3}+3(\frac{x-3}{x-3})$ $\frac{3}{x-3}=\frac{x+3(x-3)}{x-3}$ $3=x+3(x-3)$ $3=x+3x-9$ $3=4x-9$ $4x=12$ $x=3$
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