College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter 1 - Equations and Inequalities - Exercise Set 1.2: 67

Answer

$x=3$ conditional equation

Work Step by Step

$\frac{2x}{x-3}=\frac{6}{x-3}+4$ $\frac{2x}{x-3}=\frac{6}{x-3}+4(\frac{x-3}{x-3})$ $\frac{2x}{x-3}=\frac{6+4(x-3)}{x-3}$ $2x=6+4(x-3)$ $2x=6+4x-12$ $2x=4x-6$ $x=2x-3$ $x=3$
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