## College Algebra (6th Edition)

$x=59$
We may substitute the expressions involving x into the equation $y_{1}-y_{2}=-4$ and solve: $(\frac{x+1}{4})-(\frac{x-2}{3})=-4$ $(\frac{3}{3})(\frac{x+1}{4})-(\frac{4}{4})(\frac{x-2}{3})=-4$ $(\frac{3x+3}{12})-(\frac{4x-8}{12})=-4$ $\frac{(3x+3)-(4x-8)}{12}=-4$ $\frac{3x+3-4x+8}{12}=-4$ $\frac{-x+11}{12}=-4$ $(12)(\frac{-x+11}{12})=(12)(-4)$ $-x+11=-48$ $-x=-59$ $x=59$ Because we are dealing with a linear equation in one variable, there is only one answer.