Answer
$(x+2)(3x-1)$
Work Step by Step
Group the first two terms together; then, group the last two terms together to obtain:
$=(3x^2+6x) + (-x-2)$
Factor out the GCF of each group ($3x$ in the first and $-1$ in the second):
$=3x(x+2) +(-1)(x+2)$
Factor out the GCF $(x+2)$ to obtain:
$=(x+2)[3x+(-1)]
\\=(x+2)(3x-1)$
