College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Assess Your Understanding: 22

Answer

$(3x+1)(3x-1)$

Work Step by Step

$9x^2-1$ To factor the difference of two squares, we can refer to the general form that any difference of two squares can be written as, that is: $(x^2-a^2)=(x+a)(x-a)$ Therefore, the answer can be written as: $(3x+1)(3x-1)$
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