College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.5 - Factoring Polynomials - R.5 Assess Your Understanding: 41

Answer

$(2x+3)(4x^2-6x+9)$

Work Step by Step

$8x^3+27$ To factor the sum of difference of two cubes, let us remember $a^3 + b^3 = (a + b)(a^2 – ab + b^2)$ and $a^3 – b^3 = (a – b)(a^2 + ab + b^2).$ Therefore, when we factor, we get $(2x+3)(4x^2-6x+9).$
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