Answer
$\displaystyle -\frac{8x^{3}z}{9y}$
Work Step by Step
We simplify:
$\displaystyle \frac{(-2)^{3}x^{4}(yz)^{2}}{3^{2}xy^{3}z}=\frac{-8x^{4}y^{2}z^{2}}{9xy^{3}z^1}
=-\frac{8}{9}x^{4-1}y^{2-3}z^{2-1}
=-\frac{8}{9}x^{3}y^{-1}z^{1}
=-\frac{8x^{3}z}{9y}$
