Answer
$\dfrac{1}{9}$
Work Step by Step
RECALL:
(1) $a^m \cdot a^n = a^{m+n}$
(2) $a^{-m} = \dfrac{1}{a^m}, a \ne 0$
Use rule (1) above to obtain:
$=3^{-6+4}
\\=3^{-2}$
Use rule (2) above to obtain:
$=\dfrac{1}{3^2}
\\=\dfrac{1}{9}$
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 79
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