College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.2 - Algebra Essentials - R.2 Assess Your Understanding - Page 27: 92

Answer

$\displaystyle \frac{1}{x^{3}y}$

Work Step by Step

We simplify: $\displaystyle \frac{x^{-2}y^1}{xy^{2}}=x^{-2-1}y^{1-2}=x^{-3}y^{-1}=\frac{1}{x^{3}y}$
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