College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.1 - Real Numbers - R.1 Assess Your Understanding - Page 16: 73

Answer

$\dfrac{23}{20}$

Work Step by Step

Make the fractions similar using their LCD of 20 to obtain: $=\dfrac{3(5)}{4(5)} + \dfrac{2(4)}{5(4)} \\=\dfrac{15}{20}+\dfrac{8}{20} \\=\dfrac{15+8}{20} \\=\dfrac{23}{20}$
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