College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.1 - Real Numbers - R.1 Assess Your Understanding - Page 16: 84

Answer

$\dfrac{25}{6}$

Work Step by Step

RECALL: (1) $\dfrac{\frac{a}{b}}{\frac{c}{d}}=\dfrac{a}{b} \div \dfrac{c}{d}$ (2) $\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b}\cdot \dfrac{d}{c}$ Use the rules above to obtain: $\dfrac{5}{21} \div \dfrac{2}{35} \\=\dfrac{5}{21} \cdot \dfrac{35}{2}$ Cancel the common factor, $7$, and then simplify to obtain: $\require{cancel} =\dfrac{5}{\cancel{21}3} \cdot \dfrac{\cancel{35}5}{2} \\=\dfrac{5}{3} \cdot \dfrac{5}{2} \\=\dfrac{5(5)}{3(2)} \\=\dfrac{25}{6}$
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