Answer
$R=0$
$x+4$ is a factor.
Work Step by Step
$f\left( x\right) =x^{6}-16x^{4}+x^{2}-16=\left( x+4\right) q\left( x\right) +R$
$\Rightarrow f\left( -4\right) =0=R$
Since $R=0$, $x+4$ is a factor.
College Algebra (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0321979478
ISBN 13:
978-0-32197-947-6
Chapter 5 - Section 5.5 - The Real Zeros of a Polynomial Function - 5.5 Assess Your Understanding - Page 387: 18
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