Chapter 4 - Section 4.3 - Quadratic Functions and Their Properties - 4.3 Assess Your Understanding - Page 300: 74

See graph Intersection points area $1, -5)$ and $(-4, 7)$

$f(x) = -2x - 1$ $g(x) = x^2 - 9$ Solving $f(x) = g(x)$ $ => x^2 -9 = -2x - 1$ $=> x^2 + 2x - 8 = 0$ $=> (x-2)(x+4) = 0$ $=> x = -4, 2$ $f(-4) = g(-4) = 7$ $f(2) = g(2) = -5$ Intersection points area $1, -5)$ and $(-4, 7)$