Chapter 4 - Section 4.3 - Quadratic Functions and Their Properties - 4.3 Assess Your Understanding - Page 300: 77

See graph Intersection points area $(-1, -6)$ and $(2, 6)$

$f(x) = -x^2 + 5x$ $g(x) = x^2 + 3x - 4$ Solving $f(x) = g(x)$ $ => -x^2 + 5x = x^2 + 3x - 4$ $=> 2x^2 - 2x - 4 = 0$ $=> x^2 - x - 2 = 0$ $=> (x-2)(x+1) = 0$ $=> x = -1, 2$ $f(-1) = g(-1) = -6$ $f(2) = g(2) = 6$ Intersection points area $(-1, -6)$ and $(2, 6)$