Chapter 4 - Section 4.3 - Quadratic Functions and Their Properties - 4.3 Assess Your Understanding - Page 300: 78

See graph Intersection points area $(0, -6)$ and $(3, 6)$

$f(x) = -x^2 + 7x - 6$ $g(x) = x^2 + x - 6$ Solving $f(x) = g(x)$ $ => -x^2 + 7x - 6 = x^2 + x - 6$ $=> 2x^2 - 6x = 0$ $=> x^2 - 3x = 0$ $=> x(x-3) = 0$ $=> x = 0, 3$ $f(0) = g(0) = -6$ $f(3) = g(3) = 6$ Intersection points area $(0, -6)$ and $(3, 6)$