## College Algebra (10th Edition)

RECALL: The coordinates of the vertex of a quadratic function $f(x) = ax^2+bx+c$ are: $\left(\frac{-b}{2a}, f(-\frac{2}{a})\right)$ The given quadratic function has $a=-1, b=4, c=5$. Thus, the coordinates of the function's vertex are: $=\left(-\frac{4}{2\cdot(-1)}, f(-\frac{4}{2\cdot(-1)})\right) \\=\left(-\frac{4}{-2}, f(-(-2)\right) \\=(2, f(2))$ The vertex has a y-coordinate of $f(2)$. Therefore, the given statement is true.