Answer
See image
Work Step by Step
Completing the square,
$\begin{aligned}f(x)&=x^{2}-6x-1\\&=\left(x^{2}-6x+9\right)-1-9\\&=(x-3)^{2}-10\end{aligned}$
Let $f_{1}(x)=x^{2}$.
Then, $f(x)=f_{1}(x-3)-10$.
Starting with the graph of $f_{1}(x)=x^{2}$ (black-dashed),
shift it right 3 units to obtain the graph of $f_{1}(x-3)$ (green dashed),
and then lower it $10$ units down to obtain $f_{1}(x-3)-10=f(x)$ (red).
