## College Algebra (10th Edition)

$x$-intercepts: $-3$ and $3$ $y$-intercept: $9$
RECALL: (1) The intercepts of a function are the points where its graph touches or crosses the x axis or the y axis. (2) The x-intercept can be found by letting $y=0$ and then solving for $x$. (3) The y-intercept can be found by letting $x=0$ and then solving for $y$ Letting $y=0$ and then solving for $x$ gives: $y=x^2-9 \\0=x^2-9 \\9=x^2 \\\pm\sqrt{9} = \sqrt{x^2} \\\pm3 = x$ Letting $x=0$ and then solving for $y$ gives: $y=x^2-9 \\y=0^2-9 \\y=0-9 \\y=9$ Thus, the intercepts of the function are: $x$-intercepts: $-3$ and $3$ $y$-intercept: $9$