Answer
$x\leq-\frac{17}{9}$
Work Step by Step
We simplify as follows:
$2(3x+5)^{-1}\leq-3$
$\frac{2}{3x+5}\leq-3$
$2\leq-3(3x+5)$
$2\leq-9x-15$
$9x\leq-17$
$x\leq-\frac{17}{9}$
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